Probability of Not Placing Letters into Correct Envelopes Using Derangements

Probability of Not Placing Letters into Correct Envelopes Using Derangements

In this article, we will explore the problem of finding the probability that none of the 5 letters are placed into the correct envelopes using the concept of derangements. A derangement is a permutation of a set where none of the elements appear in their original position. Let's delve into the step-by-step solution to this problem.

Step 1: Total Arrangements

The first step involves calculating the total number of ways to arrange 5 letters in 5 envelopes. This is given by the factorial of the number of letters (or envelopes). The factorial (denoted as !) of a number n is the product of all positive integers less than or equal to n.

For 5 letters, the total number of arrangements (denoted as N) is:

N 5! 5 times; 4 times; 3 times; 2 times; 1 120

Step 2: Derangements

A derangement is the specific type of permutation where none of the elements appear in their original position. The formula for the number of derangements (denoted as !n) of n items is given by:

!n n! times; sum;_{i0}^{n} (-1)^i / i!

For 5 items (n 5), the number of derangements (!5) is calculated as follows:

!5 5! times; (-1^0 / 0!) - (-1^1 / 1!) (-1^2 / 2!) - (-1^3 / 3!) (-1^4 / 4!) - (-1^5 / 5!)

Let's break down the calculation step-by-step:

5! 120 !5 120 times; (-1^0 / 0!) - (-1^1 / 1!) (-1^2 / 2!) - (-1^3 / 3!) (-1^4 / 4!) - (-1^5 / 5!) -1^0 / 0! 1 / 1 1 -1^1 / 1! -1 / 1 -1 -1^2 / 2! 1 / 2 0.5 -1^3 / 3! -1 / 6 -0.1667 -1^4 / 4! 1 / 24 0.0417 -1^5 / 5! -1 / 120 -0.0083

Now, summing up these terms:

!5 120 times; (1 - 1 0.5 - 0.1667 0.0417 - 0.0083)

Cleaning up the terms inside the parentheses:

1 - 1 0 0 0.5 0.5 0.5 - 0.1667 0.3333 0.3333 0.0417 0.375 0.375 - 0.0083 0.3667

Multiplying by 120:

!5 120 times; 0.3667 44

Step 3: Probability Calculation

Finally, we can calculate the probability (denoted as P) that none of the letters are placed in the correct envelopes using the formula:

Pnone correct !5 / 5!

Substituting the values:

Pnone correct 44 / 120 11 / 30

Hence, the probability that the letters are not put into the correct envelopes is:

boxed{11 / 30}

Conclusion

Using the concept of derangements, we have determined the probability that none of the 5 letters are placed into the correct envelopes to be 11/30. This is a specific type of permutation where none of the elements appear in their original position. This problem is a classic example in combinatorics and is often used to illustrate the application of derangements in probability theory.