Understanding Polynomial Division and Remainders
In this article, we will explore the process of finding the remainder of a polynomial when it is divided by a given polynomial. Specifically, we will solve the problem of finding the values p and q for the polynomial P(x) in the context of the division by x^2 - 5x 6.
Problem Statement
We are given that the remainder of the polynomial P(x) when divided by x - 2 is 3, and when divided by x - 3 is 2. We need to find the remainder when P(x) is divided by x^2 - 5x 6, which factors into (x - 2)(x - 3). The remainder is of the form P(x) px q.
Step-by-Step Solution
The problem is boiled down to setting up and solving a system of equations based on the given conditions. Here is a detailed breakdown of the solution process:
Step 1: Understand the Given Remainders
We know the following:
The remainder of P(x) when divided by x - 2 is 3: The remainder of P(x) when divided by x - 3 is 2:This translates to:
P(2) 3 P(3) 2Step 2: Formulate the Remainder
When P(x) is divided by x^2 - 5x 6, the remainder is a linear polynomial px q since the divisor is a quadratic polynomial.
Step 3: Set Up the System of Equations
Using the fact that the polynomial x^2 - 5x 6 factors into (x - 2)(x - 3), we can express the system of equations as:
P(2) 2p q 3 (from P(2) 3) P(3) 3p q 2 (from P(3) 2)Step 4: Solve the System of Equations
Subtract the first equation from the second equation to eliminate q: [ (3p q) - (2p q) 2 - 3 ] This simplifies to: [ p -1 ] Now substitute p -1 back into the first equation to find q: [ 2(-1) q 3 ] [ -2 q 3 ] [ q 5 ] Thus, the values of p and q are:
boxed{-1} and boxed{5}
Conclusion
In this solution, we effectively used the properties of polynomial division and the remainder theorem to find the values of p and q. This method involves setting up and solving a system of linear equations based on the given remainders of the polynomial when divided by specific linear factors.
Related Keywords: polynomial division, remainder theorem, system of equations